How do you combine $\frac{x^{2} + 3 x + 2}{x^{2} - 16} + \frac{3 x + 6}{x^{2} - 16}$ $(x^2 +3x +2)/(x^2-16) + (3x +6)/(x^2-16)$ ?

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Answer 1 · 2015-05-19T10:38:17

When you have a sum or subtraction of two fractions with the same denominator, you just sum/subtract the numerators, as follows:

$\frac{x^{2} + 3 x + 2 + 3 x + 6}{x^{2} - 16}$ $(x^2+3x+2+3x+6)/(x^2-16)$

$\frac{x^{2} + 6 x + 8}{x^{2} - 16}$ $(x^2+6x+8)/(x^2-16)$

How do you combine x2+3x+2x2−16+3x+6x2−16(x^2 +3x +2)/(x^2-16) + (3x +6)/(x^2-16)?