How do you find the solution of the system of equations #x+y=6 # and #x-y=2#?

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Answer 1 · 2015-05-19T15:00:53

Let's isolate one variable in one equation and take the value we find and substitute it in the other equation, as follows.

Let's isolate #x# in the first, for example:

#x=6-y#

Nos, substituting it in the second:

#(6-y)-y=2#
#6-2y=2#
#-2y=-4#
#y=1/2#

If #y=1/2# and #x=6-y#, then

#x=6-1/2#
#x=11/2#