How do you simplify #(sqrta- sqrtb)/(sqrta+sqrtb)#?

2 Answers
May 19, 2015

Multiply both numerator and denominator by #sqrta - sqrtb#

#(sqrta - sqrtb)/(sqrta + sqrtb)= (sqrta - sqrtb)^2/(a - b)#

May 19, 2015

In this case, simplifying means rationalizing the denominator, that is getting rid of its square roots.

This can be done by using a well known algebraic identity: #x^2 - y^2 = (x+ y)(x - y)#.

In our case, we have to multiply the fraction by #(sqrt a - sqrt b)#:

#((sqrt a - sqrt b)(sqrt a - sqrt b)) / ((sqrt a - sqrt b)(sqrt a + sqrt b))# = #((sqrt a - sqrt b)^2) / ((sqrt a)^2 - (sqrt b)^2)# = #((sqrt a - sqrt b)^2) / (a -b)#