How do you factor #x^2 + 6xy + 9y^2#?

1 Answer
May 20, 2015

You can factor this by grouping.

The coefficients of #x^2# and #y^2# are, respectively, #1# and #9#, the product of which is #9#, which, in turn, can be factored in #(3)(3)#.

So, we can rewrite our function as

#x^2+3xy+9y^2+3xy#

and factor it by two groups of two terms each:

#color(green)(x)(color(blue)(x+3y)) + color(green)(3y)(color(blue)(3y+x))#

We can see that the parenthesis of each term are exactly the same, so we can use them as the common multiple of the whole equation that are multipling the rest:

#(color(blue)(x+3y))(color(green)(x+3y))#

Done!