Question

How do you find the integral `( x^4 - 3x^3 + 6x^2 - 7 ) dx`?

Answer 1

Have a look:

hope it helps!

Answer 2

by definition, we know that `intx^ndx=(x^(n+1))/(n+1)`

Thus,

`int(x^4-3x^3+6x^2-7)dx=(x^5)/5-(3x^4)/4+2x^3-7x+c`