Question

How do you prove #(2 cos 3x)/(sin 4x - sin 2x)=cscx?

Answer 1

f(x) = `(2cos 3x)/(sin 4x - sin 2x)`

From trig identity -> (sin 4x - sin 2x) = 2cos 3x.sin x

`f(x) = (2cos 3x)/(2cos 3x.sin x)` = `1/sin x` = csc x