How do you factor #125x^3 + 8y^3#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. May 21, 2015 #125x^3+8y^3# #=(5x)^3+(2y)^3# #=(5x+2y)((5x)^2-(5x)(2y)+(2y)^2)# #=(5x+2y)(25x^2-10xy+4y^2)# using the standard factorisation: #(a^3+b^3) = (a+b)(a^2-ab+b^2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 9228 views around the world You can reuse this answer Creative Commons License