How do you factor #4x^2 - 24x + 32#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. May 23, 2015 #4x^2-24x+32 = 4(x^2-6x+8)# #= 4(x^2-(2+4)x+(2xx4))# #= 4(x-2)(x-4)# The method by which #(x^2-6x+8)# is factored is sometimes called "Splitting the middle" - finding two numbers whose sum is the middle coefficient and whose product is the constant term. Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 3623 views around the world You can reuse this answer Creative Commons License