Question

The sum of three consecutive integers is 915, what are the integers?

Answer 1

`304`, `305` and `306`

To solve this problem you could solve:

`915 = (n-1) + n + (n+1) = 3n`

Then divide both sides by `3` to get `n = 305`.

Answer 2

`304+305+306`

You can write your problem as:

`n+(n+1)+(n+2)=915`

`3n+3=915`

`3n=912`

`n=912/3=304`

so you have

`304+305+306=915`