Question

How do you write the slope-intercept form of an equation of the line that passes through the given point and is perpendicular to the equation given (4, -5), `2x-5y= -10`?

Answer 1

`y=-5/2x+5`

`2x-5y=10`

`5y=2x-10`

`y=2/5x-2`

So `m=2/5`

For perpendicular lines: `mm'=-1`

So `m'=-5/2`

`y=m'x+c`

So:

`-5=(-5/2)xx4+c`

`c=-5+10=5`

So:

`y=-5/2x+5`