Question

How do you solve by completing the square for `y=3x^2+24x+8`?

Answer 1

`y = 3(x^2 + 8x + 16) - 48 + 8`

`y = 3(x + 4)^2 - 40`

`(x + 4) ^2 = 40/3 -> (x + 4) = +- (2sqrt10)/(sqrt3)`=`+- (2sqrt30)/3`

`x = -24/6 +- (2sqrt30)/18 = -6 +- (sqrt30)/9`