Question

How do you factor `2x^2+3x-2`?

Answer 1

You can find its roots and then turn them into factors. I"ll use Bhaskara to find the roots.

`(-3+-sqrt(9-4(2)(-2)))/4`
`(-3+-5)/4`
`x_1=-2`, which is the same as the factor `x+2=0`
`x_2=1/2`, which is the same as the factor `2x-1=0`

Thus,

`2x^2+3x-2=(x+2)(2x-1)`

Answer 2

`2x^2 + 3x - 2`

Product = - 4
Sum = +3
Factors = 4, - 1
=

So spiting it up

`2x^2 - x + 4x - 2`

`x ( 2x - 1)+2(2x - 1)`
`(x + 2)(2x -1)`
=

Hence factored