How do you factor #16m^4 - 81#? Algebra Polynomials and Factoring Factoring Completely 1 Answer Safi May 30, 2015 #16m^4-81# Factorize: #=(4m^2)^2-(9)^2# Recall: #(a)^2-(b)^2=(a+b)(a-b)# #=(4m^2+9)(4m^2-9)# #=(4m^2+9)[(2m)^2-(3)^2]# ANSWER: #color(green)[=(4m^2+9)(2m+3)(2m-3)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 3441 views around the world You can reuse this answer Creative Commons License