How do you factor 16m^4 - 81? Algebra Polynomials and Factoring Factoring Completely 1 Answer Safi May 30, 2015 16m^4-81 Factorize: =(4m^2)^2-(9)^2 Recall: (a)^2-(b)^2=(a+b)(a-b) =(4m^2+9)(4m^2-9) =(4m^2+9)[(2m)^2-(3)^2] ANSWER: color(green)[=(4m^2+9)(2m+3)(2m-3) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely 2x^2-8? Which method do you use to factor 3x(x-1)+4(x-1) ? What are the factors of 12x^3+12x^2+3x? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor 12c^2-75 completely? How do you factor x^6-26x^3-27? How do you factor 100x^2+180x+81? See all questions in Factoring Completely Impact of this question 3646 views around the world You can reuse this answer Creative Commons License