Question

How do you solve `2^x = 10`?

Answer 1

For this kind of question you should use logarithm.
For example;
`a^b = c => log_a(c) =b`
Therefore for our question;
`2^x=10 => log_2(10)=x => x= log_2(2*5) => x= log_2(2) +log_2(5)`
`=> x=1+log_2(5)`
`x= 1+2.32 =ul3.32`