How do you solve the system #2x +4y = 8# and #-5x +3y = 5#?
1 Answer
Jun 2, 2015
Given:
Multiply the first by 5 and the second by 2:
So:
Back in the first equation:
Given:
Multiply the first by 5 and the second by 2:
So:
Back in the first equation: