How do you factor #18b^2+24bt+8t^2#?

1 Answer
Jun 3, 2015

Given #18b^2+24bt+8t^2#

If you extract the obvious common factor of #2#
#color(white)("XXXX")##2(9b^2+12bt+4t^2)#
#color(white)("XXXX")##=2((3b)^2 + 2(3b)(2t) + (2t)^2)#
we end up with some obvious squares for the first and last terms and using their roots can see that together they will generate the middle term.
#color(white)("XXXX")##2(3b+2t)^2#