Question

How do you solve by completing the square for `2x^2 - 4x + 5 = 0`?

Answer 1

`2x^2-4x+5 = 0`

`color(white)("XXXX")` `2(x^2-2x) = -5`

`color(white)("XXXX")` `2(x^2-2x+1) = -5 +2`

`color(white)("XXXX")` `(x-1)^2 = -3/2`

`color(white)("XXXX")` `x-1 = +-sqrt(-3/2)`

note: there will be no Real solutions
`color(white)("XXXX")` `x = 1+-sqrt(3/2)i`