Question

How do you find the values of the six trigonometric functions of `t= (16 pi) / 3`?

Answer 1

On the trig unit circle:
`sin t = sin ((16pi)/3) = sin ((4pi)/3 + 4pi) = sin ((4p)/3) = - sin ((pi)/3) = -(sqrt3)/2`

`cos t = cos ((4pi)/3 + 4pi) = cos ((4pi)/3) = -cos ((pi)/3) = -1/2`

`tan t = -sqrt3`

`cot t = -(sqrt3)/3`

sec t = 1/cos t =

csct =1/sin t =