What is the period and amplitude for I(t)=120sin(10πxπ4)?

1 Answer
Jun 5, 2015

A general time-dependent wave function can be represented in the following form:

y=Asin(kxωt)

where,
A is amplitude
ω=2πT where T is time period
k=2πλ where λ is the wavelength

So, comparing with the given equation I(t)=120sin(10πxπ4), we can find:

Amplitude (A) = 120

Now, your supplied equation has no t- dependent parameter in the sine function, whereas the L.H.S. clearly indicates it is a time-dependent function [I(t)]. So, this is impossible!

Probably, your equation was supposed to be I(t)=120sin(10πxπ4t)

Under that condition,
ω=π4
π4=2πT
T=8 units