Question

Let `f(x)=1-x` and `g(x)= x^2` and `h(x)= 1/x`, how do you find g(h(x))?

Answer 1

If `g(x) = x^2`
and `h(x) = 1/x`

then `g(h(x)) = (h(x))^2 = (1/x)^2 = 1/x^2`

Sometimes this can be easier to see if you remember that the `x` in
`color(white)("XXXX")` `g(x)=x^2` and in `h(x)= 1/x`
are just place holders
and could be written as
`color(white)("XXXX")` `g(W) = W^2` and `h(Q)=1/Q`
then there is less confusion in replacing the `W` of `g(W)` with `h(x)`