How do you evaluate #[(2 + 4 * 3) - 8] + 81#?

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Answer 1 · 2015-06-05T22:47:01

To evaluate #[(2+4*3)-8]+81# use PEMDAS

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

First evaluate #(2+4*3)#
Multiplication takes precedence over addition so

#(2+4*3) = (2+12) = 14#

Next evaluate #[14-8]#

#[14-8] = 6#

Then evaluate #6+81#

#6+81 = 87#

So, in place, this sequence looks like:

#[(2+4*3)-8]+81#

#=[(2+12)-8]+81#

#=[14-8]+81#

#=6+81#

#=87#