How to use the discriminant to find out what type of solutions the equation has for #5n² + 6n + 7 = n² - 4n#?

1 Answer
Jun 6, 2015

First subtract #n^2-4n# from both sides to get:

#4n^2+10n+7 = 0#

This is of the form #an^2+bn+c = 0#, with #a=4#, #b=10# and #c=7#

The discriminant is given by the formula:

#Delta = b^2-4ac = 10^2-(4xx4xx7) = 100-112 = -12#

Since #Delta < 0# the quadratic has no real solutions. It has two distinct complex roots.

In general, the possible cases are:

#Delta = 0# : Means the quadratic has one repeated real root. If the coefficients of the quadratic are rational, that repeated root is also rational.

#Delta > 0# : Means that the quadratic has two distinct real roots. If #Delta# is also a perfect square and the coefficients of the quadratic are rational, then those roots are also rational.

#Delta < 0# : Means that the quadratic has no real roots. It has two distinct complex roots which are complex conjugates of one another.