How do you simplify sqrt2(sqrt6+sqrt8)+sqrt3? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Tessalsifi Jun 7, 2015 We are going to expand : =sqrt2*sqrt6+sqrt2*sqrt8+sqrt3 =sqrt12+sqrt16+sqrt3 =sqrt(4*3)+4+sqrt3 ( since sqrt16=4 ) =sqrt4*sqrt3+4+sqrt3 =2sqrt3+4+sqrt3 ( since sqrt4=2 ) =3sqrt3+4 Answer link Related questions How do you simplify \frac{2}{\sqrt{3}}? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify 7/(""^3sqrt(5)? How do you multiply (sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))? How do you rationalize the denominator for \frac{2x}{\sqrt{5}x}? Do you always have to rationalize the denominator? How do you simplify sqrt(5)sqrt(15)? How do you simplify (7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))? See all questions in Multiplication and Division of Radicals Impact of this question 1753 views around the world You can reuse this answer Creative Commons License