How do you solve by substitution #x + 7y = 33# and #3x - 2y = 7#?

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Answer 1 · 2015-06-07T12:00:13

#x + 7y = 33#

#x = color(red)(33 - 7y# .......equation #(1)#
#3x - 2y = 7#........equation #(2)#

Substituting equation #(1)# in #(2)# to find #y#

#3color(red)((33 - 7y)) - 2y = 7#

#99 - 21y- 2y = 7#
#-23y= 7-99#
#-23y= -92#
#color(blue)(y= 4#

Substituting #y# in equation #(1)#to find #x#
#x =33 - 7y#

#x =33 - 7.4 = 33 - 28#
#color(blue)(x =5#

The solution for the system of equations is:
#color(blue)( x = 5 , y=4#