Question

How do you evaluate `9-15div3(-3)^2+22`?

Answer 1

Operations in a calculation have priority rules:

powers > multiplications/divisions > additions/subtractions

`rarr 9-15/3(-3)^2+22` should be solved like this:

`9-15/3(-3)^2+22 = 9-15/3*9+22`
`= 9-5*9+22`
`= 9-45+22`
`= -36+22`
`= -14`