How do you write an equation in standard form given that the line passes through (-1, -3) and (2, 1)?

1 Answer
Jun 7, 2015

Using this formula with the given points:
(x-x_0)/(x_1-x_0)=(y-y_0)/(y_1-y_0)

The points are:

  • A(x_0,y_0)->A(-1,-3)
  • B(x_1,y_1)->B(2,1)

So the equation of the line passing through A and B becomes:
(x-(-1))/(2-(-1))=(y-(-3))/(1-(-3))

(x+1)/(2+1)=(y+3)/(4)

(x+1)/3=(y+3)/(4)

Now we must bring the equation in a "standard form" that means an equation similar to ax+by+c=0

4*(x+1)=(y+3)*3

4x +4 = 3y + 9

4x-3y-5=0

graph{4x-3y-5=0 [-3, 3,-3,3]}