Question

How do you complete the square to solve `-3x^2-18x-25= 0`?

Answer 1

`f(x) = -3(x^2 + 6x + 9) + 27 - 25 = 0`

`(x + 3)^2 = (-2)/(-3) = 2/3` --> `(x + 3) = +- sqrt2/sqrt3 = +-sqrt6/3`

`x = - 3 +-sqrt6/3`