Question

How do you find 3 consecutive integers such that their sum is 27 less than three times the smallest?

Answer 1

Call the smallest `n`; you have:
`n+(n+1)+(n+2)=27-3n`
`3n+3=27-3n`
`6n=24`
`n=4`
So:
`4+5+6=15=27-(3×4)=27-12=15`