How do you simplify #(4-sqrt3)(12 + 5 sqrt3)#?

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Answer 1 · 2015-06-08T03:30:52

You can FOIL the two brackets to get:
#(4*12)+(4*5sqrt(3))+(-sqrt(3)*12)+(-sqrt(3)*5sqrt(3))=#
#=48+20sqrt(3)-12sqrt(3)-15=#
#=33+8sqrt(3)#