How do you factor #12x^2 + 36xy + 27y^2?

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Answer 1 · 2015-06-08T04:04:59

#f(x) = 3(4x^2 + 12xy + 9y^2) = 3(2x + 3y)^2#

Answer 2 · 2015-06-08T05:31:58

Answer: #12x^2+36xy+27y^2=3(2x+3y)^2#

Problem: Factor #12x^2+36xy+27y^2#.

Factor out the GCF #3#.

#3(4x^2+12xy+9y^2)#

#(4x^2+12xy+9y^2)# is a perfect square trinomial with the pattern

#(a+b)^2=a^2+2ab+b^2#.

#a=2x#
#b=3y#

#(4x^2+12xy+9y^2)=(2x+3y)^2#

#12x^2+36xy+27y^2=3(2x+3y)^2#