Question

A cell of e.m.f. E and internal resistance r is connected across an external resistance nr.The ratio of terminal potential difference to e.m.f. is?...in terms of n only? Thank u!!!

Answer 1

Terminal potential drop/source emf =n/1+n

Explanation:

In order to find V(terminal voltage), apply voltage division rule.

Voltage division rule:

Voltage drop across "nr"=`E*(nr)/(nr+r)`
`V=E*(nr)/(r(1+n))`
`V=E*(ncancelr)/(cancelr(1+n)`
`V/E=n/(1+n)`