Question

How do you solve by completing the square for `-3x^2 + 8x + 7 = 0`?

Answer 1

Solve:`y = -3x^2 + 8x + 7 = 0`

Explanation:

`y = -3(x^2 - (8x)/3 + 16/9 - 16/9 - 7/3)`

`y = -3(x - 4/3)^2 + 16/3 + 7`

`-3(x - 4/3)^2 = -16/3 - 7 = -37/3`

`(x - 4/3)^2 = 37/9 -> (x - 4/3) = +- (sqrt37)/3`

`x = 4/3 +- (sqrt37)/3`