Question

How do you solve `Sin(2x)=sin((x/3)-2)`?

Answer 1

`x=-6/5`

Explanation:

Given that
`sin(2x)=sin(x/3-2)`
From equity,angles must be equal.
`cancel(sin)(2x)=cancel(sin)(x/3-2)`
`2x=x/3-2`
`=>6x=x-6`
`=>5x=-6`
`=>x=-6/5`

which is required solution.