How do you factor #6x^2-12x#? Algebra Polynomials and Factoring Factoring Completely 1 Answer George C. Jun 10, 2015 #6x^2-12x = 6x(x-2)# Explanation: Both terms are divisible by #6# and by #x#. once you have separated those factors out, only a linear term remains. #6x^2-12x# #=(6*x*x) - (6*x*2)# #=6*x*(x-2)# #=6x(x-2)# Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 16634 views around the world You can reuse this answer Creative Commons License