How do you solve the inverse trig function cos (arccos 3pi)? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties 1 Answer Luca F. Jun 11, 2015 It does not exist. Explanation: y=arccos(x) is a function defined in the interval [-1,1] So it does not exist for the value 3pi>1. arccos(3pi) does not make any sense! Answer link Related questions How do you use the properties of inverse trigonometric functions to evaluate tan(arcsin (0.31))? What is \sin ( sin^{-1} frac{sqrt{2}}{2})? How do you find the exact value of \cos(tan^{-1}sqrt{3})? How do you evaluate \sec^{-1} \sqrt{2} ? How do you find cos( cot^{-1} sqrt{3} ) without a calculator? How do you rewrite sec^2 (tan^{-1} x) in terms of x? How do you use the inverse trigonometric properties to rewrite expressions in terms of x? How do you calculate sin^-1(0.1)? How do you solve the inverse trig function cos^-1 (-sqrt2/2)? How do you solve the inverse trig function sin(sin^-1 (1/3))? See all questions in Inverse Trigonometric Properties Impact of this question 4835 views around the world You can reuse this answer Creative Commons License