How do you solve the system #3y=-1/2x+2# and #y=-x+9#?

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Answer 1 · 2015-06-14T23:06:01

Substitute the expression for #y# from the second equation into the first and solve for #x# to get #x = 10# and #y = -1#

Substitute the expression for #y# from the second equation into the first...

#-1/2x+2 = 3y = 3(-x+9) = -3x+27#

Add #3x# to both sides to get:

#5/2x+2 = 27#

Subtract #2# from both sides to get:

#5/2x = 25#

Multiply both sides by #2/5# to get:

#x = 10#

Then #y = -x+9 = -10+9 = -1#