Question

How do you find the area of the triangle given b= 14, C= 110 degrees, B= 25 degrees?

Answer 1

Area of triangle: s = (1/2) bc.sin A

Explanation:

Angle A = 180 - B - C = 180 - 110 - 25 = 45 deg
sin C = sin 110 = 0.94; sin A = sin 45 = 0.707
sin B = sin 25 = 0.42.
b = 14; Find c
`c = b(sin c/sin B) = 14(0.94/0.42) = 31.38`

Area of triangle: `s = (bc.sin A)/2 = (14/2)(31.33)(0.707) = 155.05`