Question

How can I draw the following ethers: 1-propoxypentane, 2-ethoxybutane, 1-methoxy-4-chlorohexane, and 3-butoxy-2,4-dimethyloctane?

Answer 1

You draw the main chain. Then you attach the alkoxy group to the appropriate carbon atom.

Explanation:

1-Propoxypentane

Pentane is a chain of 5 carbon atoms.

The propoxy group is a 3-carbon chain with an `"O"` atom at `"C-1"`.

Draw a chain of five carbon atoms and attach the 1-propoxy group to `"C-1"` of the chain.

2-Ethoxybutane

Attach an ethoxy group to `"C-2"` of a butane chain.

4-Chloro-1-methoxyhexane

Draw a 6-carbon chain. Attach a methoxy group to `"C-1"` and a `"Cl"` atom to `"C-4"`.

3-Butoxy-2,4-dimethyloctane

Draw an 8-carbon chain. Attach a butoxy group to `"C-3"` and methyl groups to `"C-2"` and `"C-4"`.