Question

Question #8acfd

Answer 1

The value of `n` is `root(5)(10)/5`

Explanation:

When you substitute values for x,a and b you get:
`2=10log_10 ((25n)/5)`
`2=10log_10 5n`
`1/5=log_10 5n`
`log_10 (10^(1/5))=log_10 5n`
`10^(1/5)=5n`
`n=10^(1/5)/5`