How do you multiply #(2sqrt21)(3sqrt6)#?

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Answer 1 · 2015-06-19T18:25:59

#(2sqrt(21))(3sqrt(6)) = 6sqrt(21*6) = 6sqrt(9*14) = 18sqrt(14)#

#(2sqrt(21))(3sqrt(6))#

#= 2*sqrt(21)*3*sqrt(6)#

#=2*3*sqrt(21)*sqrt(6)#

#=6*sqrt(21*6)#

#=6*sqrt(9*14)#

#=6*sqrt(9)*sqrt(14)#

#=6*3*sqrt(14)#

#=18sqrt(14)#

If #a, b > 0# then #sqrt(ab) = sqrt(a)sqrt(b)#