Question

How do you solve the system `-3x -8y = -9` and `x+ 16y =3`?

Answer 1

The solution is: `{(x=3),(y=0):}`

Explanation:

First you multiply the first equation by 2 and get:

`{(-6x-16y=-18),(x+16y=3):}`

Now you can add both equations to eliminate `y`.

`-5x=-15`
`x=3`

Now if you substitute `x` in the 2nd equation you can calculate that: `y=0`