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Answer 1 · 2015-06-21T19:00:49

The solution is : $x=e vv x=1/e$

The logarythms have different bases, so first you have to change base using formula:

$log_ax=log_ba/log_bx$

In this case we get:

$log_ex-1/log_ex=0$

$(log_ex)^2-1=0$

$(log_ex-1)(log_ex+1)=0$

$log_ex-1=0 vv log_ex+1=0$

$log_ex=1 vv log_ex=-1$

$x=e vv x=1/e$