Question

How do you solve `4(3-y)+y = 22+2y`?

Answer 1

I found: `y=-2`

Explanation:

First multiply the `4`:
`12-4y+y=22+2y`
now collect all the `y` on one side (left for example):
`-4y+y-2y=-12+22`
Add:
`-5y=10`
`y=10/-5=-2`

Answer 2

`y=(-2)`

Explanation:

`4(3-y)+y = 22+2y`
multiply out the first term:
`color(white)("XXXX")` `12-4y + y = 22+2y`
combine the `y` terms on the left side
`color(white)("XXXX")` `12-3y = 22+2y`
add `3y` and subtract `22` from both sides
`color(white)("XXXX")` `-10 = 5y`
divide both sides by `5` (and reverse equation for more normal form)
`color(white)("XXXX")` `y = -2`