Question

How do you reduce `7y + 2y^2 - 7` by `3 - 4y`?

Answer 1

`11y +2y^2-10` is `(3-4y)` less than `7y+2y^2-7`;
that is, if you reduce `7y+2y^2-7` by `3-4y` you get `11y+2y^2-10`

Explanation:

The phrasing is a little unusual but "reducing" A by B means subtracting B from A.

`(color(red)(7y+2y^2-7)) - (color(blue)(3-4y))`

`=color(red)(7y)color(blue)(+4y) + 2y^2 color(red)(-7) color(blue)(-3)`

`=11y - 2y^2 -10`