How do you find the exact values of six trigonometric functions of t given #(sqrt 3/2, 1/2)#?

1 Answer
Jun 25, 2015

#sin(t) = 1/2#;#color(white)("XXXX")##cos(t)=sqrt(3)/2#;#color(white)("XXXX")##tan(t)=1/sqrt(3)#
#csc(t)=2#;#color(white)("XXXX")##sec(t)=2/sqrt(3)#;#color(white)("XXXX")##cot(t)=sqrt(3)#

Explanation:

Assuming the point given is the terminal point of an angle, #t#, in standard Cartesian coordinate position,
the angle is #30^o# and the six trigonometric values can be read directly from the image below, base on the definition of those functions.
enter image source here