How do you write y=3/8x-3/4y=38x34 in standard form?

1 Answer
Jun 28, 2015

y=3/8x-3/4y=38x34 in standard form is 3x-8y=63x8y=6.

Explanation:

Standard form for a linear equation is Ax+By=CAx+By=C.

y=3/8x-3/4y=38x34

Simplify 3/8x38x to (3x)/83x8.

Subtract (3x)/83x8 from both sides of the equation.

(-3x)/8+y=-3/43x8+y=34

Multiply both sides by -11.

(-3x)/8(-1)+y(-1)=-3/4(-1)3x8(1)+y(1)=34(1) =

(3x)/8-y=3/43x8y=34

Multiply both sides by 88.

((3x)*8)/8-y(8)=((3)*8)/4(3x)88y(8)=(3)84 =

((3x)*cancel8^1)/(cancel 8^1)-y(8)=((3)*cancel8^2)/(cancel4^1) =

3x-8y=6