How do you solve by substitution #2x-y=32# and #y-5x=13#?

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Answer 1 · 2015-07-01T08:11:34

#color(blue)(x=-15, y=-62#

#2x-y=32 #.........equation #(1)#

#y-5x=13#
#color(blue)(y=13 + 5x# ........equation #(2)#

Substituting equation #2# in #1# to find #x#:

#2x-y=32 #

#2x-color(blue)((13 + 5x))=32 #

#-3x=32 +13 #

#-3x=45#

#color(blue)(x=-15#

Finding #y# from equation #2#
#y=13 +5x#

#y=13 -75#

#color(blue)(y = -62#
The solution for the equation is:
#color(blue)(x=-15, y=-62#