How do you write an equation in standard form for a line with slope of 2/3 and y-intercept (0,5) ?

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Answer 1 · 2015-07-01T22:11:51

I found:
#2x-3y=-15#

In general the equation of a line can be written in the form:
#y=mx+c#
where:
#m# is the slope
#c# is the y-intercept.

In your case you have:
#y=2/3x+5#
or in standard form (rearranging):

#3y=2x+15# dealing with #3# in the denominator, and collecting:
#2x-3y=-15#