What is the standard form for #y = 6(x - 2)^2 - 8#?
1 Answer
Jul 2, 2015
Standard form of y = 6(x - 2)^2 - 8
Explanation:
To find the standard form, develop the vertex form.
y = 6(x^2 - 4x + 4) - 8 = 6x^2 - 24x + 16
