Question #edcc7

1 Answer
Rogan V.
Jul 2, 2015

The effective magnetic moment of #SC^(3+)# is zero.

Explanation:

The oxidation state of 3+ indicates that Scandium which has an electronic configuration of #1s^2#, #2s^2#, #2p^6#, #3s^2#, #3p^6#, #3d^1#, #4s^2# loses 3 electrons, so therefore it loses the two from #4s^2# and the one electron from #3d^1#.

The equation to calculate the Bohr Magneton (B.M.) of the magnetic moment is:

B.M. = #sqrt(n(n+2))#

n represents unpaired electrons of the atom in question

Hence because the #Sc^(3+)# has an even number of electrons in each orbital it tells us that they are all paired, meaning no unpaired electrons. Thus 0 substituted into the above equation will yield an answer of 0 B.M.

Hope I helped :)

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